Answer
See below
Work Step by Step
The mean of $n$ numbers is the sum of the numbers divided by $n$. The median of $n$ is the middle number of the numbers when they are in order (and the mean of the middle $2$ numbers if $n$ is even). The mode of $n$ numbers is the number or numbers that appear(s) most frequently. Hence here the mean: $\frac{231+232+244+246+246+250+258+261}{8}=246$, the median is the mean of the middle items in the sequence $231,232,244,246,246,250,258,261$, which is: $246$, the mode is $246$. The range is the difference between the largest and the smallest data value. The standard deviation of $x_1,x_2,...,x_n$ is (where $\overline{x}$ is the mean of the data values): $\sqrt{\frac{(x_1-\overline{x})^2+(x_2-\overline{x})^2+...+(x_n-\overline{x})^2}{n}}$. Hence here the range is: $261-231=30$ and the standard deviation is: $\sqrt{\frac{(231-246)^2+(232-246)^2+...+(261-246)^2}{8}}\approx10.062$
