Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 11 Data Analysis and Statistics - 11.2 Apply Transformations to Data - 11.2 Exercises - Quiz for Lessons 11.1.11.2 - Page 755: 2

Answer

See below.

Work Step by Step

The mean of $n$ numbers is the sum of the numbers divided by $n$. The median of $n$ is the middle number of the numbers when they are in order (and the mean of the middle $2$ numbers if $n$ is even). The mode of $n$ numbers is the number or numbers that appear(s) most frequently. Hence here the mean: $\frac{14+15+17+18+19+19+23+24}{8}=18.625$, the median is the mean of the middle items in the sequence $14,15,17,18, 19,19, 23, 24$, which is: $(18+19)/2=18.5$, the mode is $19$. The range is the difference between the largest and the smallest data value. The standard deviation of $x_1,x_2,...,x_n$ is (where $\overline{x}$ is the mean of the data values): $\sqrt{\frac{(x_1-\overline{x})^2+(x_2-\overline{x})^2+...+(x_n-\overline{x})^2}{n}}$. Hence here the range is: $24-14=10$ and the standard deviation is: $\sqrt{\frac{(14-18.625)^2+(15-18.625)^2+...+(24-18.625)^2}{8-1}}\approx3.2763$
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