Answer
See below
Work Step by Step
We have the equations of resistance $R=\frac{V}{I}$, potential difference $V=IR$ and current $I=\frac{V}{R}$
Since $V=120\\I=0.8$, plug in $R=\frac{120}{0.8}=150$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 11 Data Analysis and Statistics - 11.1 Find Measures of Central Tendency and Dispersion - 11.1 Exercises - Mixed Review - Page 749: 41
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