Answer
See below
Work Step by Step
Substituting $n=31,r=3$ into the formula $_n C_r=\frac{n!}{(n-r)!r!}$ we have: $_{31} C_3=\frac{31!}{(31-3)!3!}=\frac{31!}{28! 3!}=4495$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 10 Counting Methods and Probability - Mixed Review of Problem Solving - Page 705: 8
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