Answer
See below
Work Step by Step
The odds in favor of a randomly chosen adult preferring to participate in gymnastics is: $\frac{101}{1013-101}=\frac{101}{912}=0.11$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 10 Counting Methods and Probability - Mixed Review of Problem Solving - Page 705: 5c
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