Answer
$$\frac{12!}{4!\left(12-4\right)!}=495$$
Work Step by Step
We know the equation for combinations:
$$nC_r = \frac{n!}{r!\left(n-r\right)!}$$
Thus, we find:
$$\frac{12!}{4!\left(12-4\right)!}=495$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 10 Counting Methods and Probability - 10.2 Use Combinations and the Binomial Theorem - 10.2 Exercises - Skill Practice - Page 694: 8
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