Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Skills Handbook - Simplifying Fractions - Exercises - Page 789: 7

Answer

9

Work Step by Step

We can solve these problems by comparing the numerator and the denominator. The denominator in the second fraction is 3 times greater than the denominator in the first fraction, so we know that the numerator of the second fraction must be 3 times greater as well. Thus, we multiply 3 times 3 to find that the missing number is 9.
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