Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Skills Handbook - Simplifying Fractions - Exercises - Page 789: 11

Answer

2

Work Step by Step

We solve these problems by comparing the numerators and the denominators. The numerator in the second fraction is 1/50 times as much as the numerator in the first fraction, so we know that the denominator of the second fraction must be 1/50 times as much as well. Thus, we multiply 100 by 1/50, finding that the missing number is 2.
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