Chapter 9 - Quadratic Functions and Equations - Mid-Chapter Quiz - Page 560: 7

Please see the graph.

$y=3x^2-6x$ vertex: $x=-b/2a$ $x=-(-6)/2(3)$ $x = 6/6 = 1$ $y = 3x^2-6x$ $y=3*1^2-6*1$ $y=3*1-6$ $y=3-6 = -3$ One other point on the curve: $x=0$ $y=3x^2-6x$ $y=3*0^2-6*0$ $y=3*0-0$ $y=0-0 = 0$ The blue line is the axis of symmetry.