Answer
Answers may vary
$y=x^2$
Work Step by Step
vertex: $x=-b/2a$
$x=-0/2*1$
$x=0$
$y=0^2$
$y=0$
We know this graph opens upward since $a$ is positive. If $a$ was negative, then the graph would open downward.
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 9 - Quadratic Functions and Equations - Mid-Chapter Quiz - Page 560: 29
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