Answer
$x=6, -7$
Work Step by Step
$x^2-13x+52=y$
$-14x+94=y$
$x^2-13x+52=-14x+94$
$x^2-13x+52+14x-94=-14x+94+14x-94$
$x^2+x-42 = 0$
$(x+7)(x-6)=0$
$x+7=0$
$x+7-7=0-7$
$x=-7$
$x-6=0$
$x-6+6=0+6$
$x=6$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 9 - Quadratic Functions and Equations - 9-8 Systems of Linear and Quadratic Equations - Lesson Check - Page 585: 2
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