Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-6 The Quadratic Formula and the Discriminant - Mixed Review - Page 573: 57

Answer

$w = .055, -6.055$

Work Step by Step

$3w^2+18w-1=0$ $(3w^2+18w-1)/3=0/3$ $w^2+6w-1/3=0$ $w^2+6w+(6/2)^2-1/3+1/3=(6/2)^2+1/3$ $w^2+6w+9 = 28/3$ $(w+3)^2 = 28/3$ $\sqrt {(w+3)^2} = \sqrt {28/3}$ $w+3 = ±3.055$ $w+3 = 3.055$ $w+3-3 = 3.055-3$ $w=.055$ $w+3 = -3.055$ $w+3-3 = -3.055-3$ $w = -6.055$
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