Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-6 The Quadratic Formula and the Discriminant - Mixed Review - Page 573: 55

Answer

$s=8.464, 1.536$

Work Step by Step

$s^2-10s+13=0$ $s^2-10s+13+(-10/2)^2=0+(-10/2)^2$ $s^2-10s+25+13=25$ $(s-5)^2+13 = 25$ $(s-5)^2+13-13= 25-13$ $(s-5)^2 = 12$ $\sqrt {(s-5)^2} = \sqrt {12}$ $s-5 = ±3.464$ $s-5 = 3.464$ $s-5+5 = 3.464+5$ $s = 8.464$ $s-5 = -3.464$ $s-5+5 = -3.464+5$ $s = 1.536$
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