Answer
$g^{2}$-100
Work Step by Step
In order to simplify the product (g+10)(g-10) we must apply the rule that states that (a+b)(a-b)=$a^{2}$-$b^{2}$. We'll set a=g and b=10, then apply the rule. Therefore,
(g+10)(g-10)=$g^{2}$-100
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 8 - Polynomials and Factoring - Mid-Chapter Quiz - Page 498: 21
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