Answer
77$x^{3}$+22$x^{2}$-33x-88=11(7x$^{3}$+2$x^{2}$-3x-8)
Work Step by Step
In order to factor 77$x^{3}$+22$x^{2}$-33x-88 we must look for the greatest factor that can factor out of all four terms. This is known as the GCF (Greatest common factor). In this case, the GCF is 11, because 11 is the greatest factor that can factor out of all four terms. After we factor out the 11, in parentheses we will leave what multiplies to the corresponding term originally. For example, for the first term, after we factor out the 11, we'll leave 7x$^{3}$ in the parentheses because 11 multiplied by 7$x^{3}$ is equal to
77$x^{3}$.
Therefore,
77$x^{3}$+22$x^{2}$-33x-88=11(7x$^{3}$+2$x^{2}$-3x-8)
