Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - Chapter Review - 8-5 and 8-6 Factoring Quadratic Trinomials - Page 525: 50

Answer

$(3x+6)(x-1)$

Work Step by Step

Factor each expression. $3x^{2}+3x-6$ Rewrite as: $3x^{2}-3x+6x-6$ Factor out a $3x$ from the first two terms and $6$ from the second two terms. $3x(x-1)+6(x-1)$ Factor: $(3x+6)(x-1)$
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