Answer
$(n-2)(2n-2)$
Work Step by Step
Factor each expression.
$2n^{2}+3n-2$
Rewrite as:
$2n^{2}-n+4n-2$
Factor out $n$ from the first two term and $2$ from the last two terms
$n(2n-2)+2(2n-2)$
Group $n$ and $2$ together
$(n-2)(2n-2)$
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