Answer
(8q+9)(8q-9)
Work Step by Step
We use the formula for the difference of squares to apply to this question.
The difference of squares formula is:
$(a-b) (a+b) = a^{2} - b^{2}$
= $64q^{2}$ - 81
*** Take the square root of $64q^{2}$ which is 8q. Becuase 8q × 8q= $64q^{2}$
*** Take the square root of 81 which is 9. Becuase 9 × 9= 81
= $(8q)^{2}−9^{2}$
In the given formula let 8q represents a and 9 represents b.
$(8q)^{2}−9^{2}$ = (8q+9)(8q-9)
