Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 515: 30

Answer

(2p+7)(2p-7)

Work Step by Step

We use the formula for the difference of squares to apply to this question. The difference of squares formula is: $(a-b) (a+b) = a^{2} - b^{2}$ = $4p^{2}$ - 49 *** Take the square root of 49 which is 7. Becuase 7 × 7= 49 *** Take the square root of $4p^{2}$ which is 2p. Becuase 2p × 2p= $4p^{2}$ = $(2p)^{2}−7^{2}$ In the given formula let a represents a and 7 represents b. $(2p)^{2}−7^{2}$ = (2p+7)(2p-7)
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