Answer
(3x-5)(4x-7)
Work Step by Step
Given the polynomial
$12x^{2}$ - 41x + 35
*** We break of the middle term into two factors that add to give -41 and multiply to give +420. The two numbers are -20 and -21.
$12x^{2}$ - 20x - 21x + 35
We take the GCD of the first two and the GCD of the last two terms.
4x(3x-5) - 7(3x-5)
We take (3x-5) and factor it out which gives us.
(3x-5)(4x-7)
