Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Mixed Review - Page 516: 64

Answer

(3x-2)(6x+7)

Work Step by Step

Given the polynomial $18x^{2}$ + 9x -14 *** We break of the middle term into two factors that add to give +9 and multiply to give -252. The two numbers are +21 and -12. $18x^{2}$ + 21x - 12x -14 We take the GCD of the first two and the GCD of the last two terms. 6x(3x-2) + 7(3x-2) We take (3x-2) and factor it out which gives us. (3x-2)(6x+7)
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