Answer
(t-7)(t+4)
Work Step by Step
Given the polynomial
$t^{2}$ -3t - 28
*** We break of the middle term into two factors that add to give -3 and multiply to give -28. The two numbers are -7 and +4.
$t^{2}$ -7t +4t - 28
We take the GCD of the first two and the GCD of the last two terms.
t(t-7) +4(t-7)
We take (t-7) and factor it out which gives us.
(t-7)(t+4)
