Answer
(w+11)(w+4)
Work Step by Step
Given the polynomial
$w^{2}$ + 15w + 44
*** We break of the middle term into two factors that add to give +15 and multiply to give +44. The two numbers are +11 and +4.
$w^{2}$ + 11w + 4w + 44
We take the GCD of the first two and the GCD of the last two terms.
w(w+11) +4(w+11)
We take (w+11) and factor it out which gives us.
(w+11)(w+4)
