Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-5 Factoring X(squared) + bx + c - Practice and Problem-Solving Exercises - Page 503: 14

Answer

$(y+1)(y+5)$

Work Step by Step

$y^2+6y+5$ Factors of 5 | Sum of Factors $\ \ \ \ \ \ 1,5\ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ 6$ Since all the terms in the binomial are added, the factors will both include addition. $y^2+6y+5=(y+1)(y+5)$ Use the FOIL method to check the answer. $(y+1)(y+5)=y^2+5y+1y+5=y^2+6y+5\checkmark$
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