Chapter 8 - Polynomials and Factoring - 8-4 Multiplying Special Cases - Practice and Problem-Solving Exercises - Page 496: 51

area of red space: $8*(x+2)^2$ $8x^2 +32x+32$

white square sidelength: $x+2$ red square sidelength: $3*(x+2)$ Area of red = red square - white square $A = (3*(x+2))^2 - (x+2)^2$ $A = 9(x+2)^2 - (x+2)^2$ $A = 8*(x+2)^2$ $8* (x+2)^2$ $8*(x+2)(x+2)$ $8*(x^2+4x+4)$ $8x^2 +32x+32$