Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-4 Multiplying Special Cases - Practice and Problem-Solving Exercises - Page 496: 45

Answer

$a^{2} - 36b^{2}$

Work Step by Step

We use the formula for the difference of squares to apply to this question. The difference of squares formula is: $(a-b) (a+b) = a^{2} - b^{2}$ In the given formula let a represents a and 6b represents b. $(a-6b) (a+6b) = a^{2} - (6b)^{2}$ = $a^{2} - 36b^{2}$
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