Answer
$\dfrac{1}{9}$
Work Step by Step
(i) $a^m \cdot a^n = a^{m+n}$
(ii) $a^{-m} = \dfrac{1}{a^m}, a\ne0$
Use the rules above to obtain:
$=3^{6-8}
\\=3^{-2}
\\=\dfrac{1}{3^2}
\\=\dfrac{1}{3(3)}
\\=\dfrac{1}{9}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 7 - Exponents and Exponential Functions - 7-5 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 443: 13
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