Answer
$\dfrac{3^2}{3^5} = 3^{-3}$
Work Step by Step
$\dfrac{a^m}{a^n} = a^{m-n}, a \ne 0$
Use the rule above to obtain:
$=3^{2-5}
\\= 3^{-3}$
Thus, the missing exponent is $-3$.
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 7 - Exponents and Exponential Functions - 7-5 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 443: 10
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