Answer
$8t^{-8}$
Work Step by Step
We start with the given expression: $4t^{-5}\times2t^{-3}$
We rearrange and regroup the expression using the associative and commutative properties of multiplication: $(4\times2)(t^{-5}t^{-3})$
We multiply the coefficients: $8(t^{-5}t^{-3})$
To multiply powers with the same base, we add the exponents: $8(t^{-5+(-3)})=8t^{-8}$