Answer
$9^{0}$
Work Step by Step
We start with the given expression: $(9)^{6}\times(9)^{-4}\times(9)^{-2}$
To multiply powers with the same base, we add the exponents.
Therefore, $(9)^{6}\times(9)^{-4}\times(9)^{-2}=9^{6+(-4)+(-2)}=9^{0}$
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