Chapter 6 - Systems of Equations and Inequalities - 6-6 Systems of Linear Inequalities - Practice and Problem-Solving Exercises - Page 399: 23

$y < -1/3*x$ $y \leq x+2$

(0, 2) and (1,3) $m = (3-2)/(1-0)$ $m = 1/1 = 1$ $y=mx+b$ $2 = 1*0+b$ $2 = 0 +b$ $2 = b$ $y= x+2$ (0,0) is part of the solution set, so the equation is $y \leq x+2$ (0,0) and (3,-1) $m = (0--1)/(0-3)$ $m = 1/-3 = -1/3$ $y=mx+b$ $0 = -1/3*0+b$ $0 = 0+b$ $0 = b$ $y=-1/3*x$ (1,1) is not part of the solution set, so the equation is $y < -1/3*x$