Answer
$y\geq-2x+2$
$y\lt 3x-2$
Work Step by Step
(0,2) and (1,0)
$m= (2-0)/(0-1)$
$m = 2/-1 = -2$
$y=mx+b$
$0 = -2*1 + b$
$0 = -2+b$
$0+2 = -2+b+2$
$2 = b$
$y=-2x+2$
(0,0) is not in the solution area, so the equation is $y\geq-2x+2$
(1,1) and (2, 4)
$m= (4-1)/(2-1)$
$m = 3/1 = 3$
$y=mx+b$
$4=3*2+b$
$4=6+b$
$4-6 = 6+b-6$
$-2 = b$
$y=3x-2$
$y=3x-2$
0,0) is not in the solution area, so the equation is $y< 3x-2$
