Answer
$y \geq-3x+3$
Work Step by Step
(0,3) and (1,0)
$m= (3-0)/(0-1)$
$m = 3/-1 = -3$
$y=mx+b$
$0 = -3*1+b$
$0 = -3 + b$
$0+3 = -3+ b + 3$
$3 = b$
$y=-3x+3$
$0 = -3*0 + 3$
$0 = 0 + 3$
$0 = 3 $ is false with $\leq$
$y \geq-3x+3$