Chapter 12 - Data Analysis and Probability - 12-4 Box-and-Whisker Plots - Practice and Problem-Solving Exercises - Page 738: 8

minimum = 5 first quartile = 8 median = 10 third quartile = 10.5 maximum = 12

$12, 10, 11, 7, 9, 10, 5$ $5, 7, 9, 10, 10, 11, 12$ 5 is the lowest value (minimum) 12 is the highest value (maximum) $5, 7, 9, 10, 10, 11, 12$ $7, 9, 10, 10, 11$ $9, 10, 10$ $10$ is the middle value $5, 7, 9, 10$ $7, 9$ $(7+9)*.5 = 8$ (first quartile) $10, 10, 11, 12$ $10, 11$ $(10+11)/2 = 10.5$ (third quartile)