Answer
Minimum=100. 1st quartile=100.5 .Median=101.3rd quartile=103. Maximum=105
Work Step by Step
You have the values: 100,100,101,101,102,104,105.
-->Minimum is the smallest value in the data set which is 100.
-->Arrange the data from least to greatest(100,100,101,101,102,04,105) to find the middle number. The median is 101.
-->The maximum is the largest value in the set which is 105.
-->The first quartile is the middle value between the minimum and median:(100,100,101,101)The middle values are 100,101. Find the average by adding the two numbers and dividing by 2: (100+101)/2=100.5
-->The third quartile is the middle value between the median and the maximum(101,102,104,105). The middle values are 102 and 104. Find the average by adding the two numbers and dividing by 2:(102+104)/2=103
Minimum=100. 1st quartile=100.5 .Median=101.3rd quartile=103. Maximum=105
