Answer
C.
Work Step by Step
For $\frac{n-2}{2-n}$, we can factor out a negative from the denominator.
$\frac{n-2}{2-n} = \frac{n-2}{-(-2+n)}=\frac{n-2}{-(n-2)}$
We can now cancel out the common factor $(n-2)$
$\frac{n-2}{-(n-2)}$ = -1