Answer
Sometimes
Work Step by Step
$(a^2+6a+5)/(2a+2) = (a+5)/2$
$(a+1)(a+5)/(2a+2) = (a+5)/2$
$(a+1)/(2a+2) = 1/2$
$(a+1)(1/2) = 1/2$
$a+1 = 1$
$a=0$
If $a = -1$, then the denominator is 0, and we can't have a number divided by zero.
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