Answer
$\frac{6}{5w}$
Work Step by Step
The area of a trapezoid is given by $A=\frac{1}{2}(b_{1}+b_{2})h$
$$A=\frac{1}{2}(b_{1}+b_{2})h=\frac{1}{2}(6+6)5w$$
The area of a square is expressed by $A=s^2$
$$A_2=s^2=(5w)^2$$
Find the ratio of the areas of the trapezoid and square
$$\frac{A_1}{A_2}=\frac{\frac{1}{2}(6+6)5w}{(5w)^2}=\frac{6}{5w}$$
