Answer
$\frac{(7z+2)}{(z-1)}$
Work Step by Step
$\frac{(7z+2)(z+3)}{z^{2}+2z-3}$
Factor the quadratic
$\frac{(7z+2)(z+3)}{(z-1)(z+3)}$
Cancel the (z+3) from top and bottom
$\frac{(7z+2)}{(z-1)}$
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