Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - Mid-Chapter Quiz - Page 619: 30

Answer

$x=5.6$

Work Step by Step

$\frac{x}{\sqrt {10}}=\frac{3\sqrt 2}{\sqrt 2+1}$ $\sqrt {10}*3\sqrt 2 = x*(\sqrt 2+1)$ $3\sqrt{20}=x*(\sqrt 2+1)$ $\frac{3\sqrt{20}}{\sqrt 2+1}=x$ $\frac{3\sqrt{20}}{\sqrt 2+1}*\frac{\sqrt2-1}{\sqrt2-1}=x$ $\frac{3\sqrt{40}-3\sqrt{20}}{\sqrt 2+1}*\frac{1}{\sqrt2-1}=x$ $\frac{3\sqrt{40}-3\sqrt{20}}{\sqrt 2*\sqrt2-\sqrt2+\sqrt2-1}=x$ $\frac{3\sqrt{40}-3\sqrt{20}}{2-1}=x$ $\frac{3\sqrt{40}-3\sqrt{20}}{1}=x$ $3\sqrt{40}-3\sqrt{20}=x$ $3(\sqrt{40}-\sqrt{20})=x$ $3(\sqrt{2*2*2*5}-\sqrt{2*2*5})=x$ $3(2\sqrt{2*5}-2\sqrt{5})=x$ $6(\sqrt{10}-\sqrt{5})=x$ $6*(3.162-2.236)=x$ $6*.926 = x =5.556$
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