Answer
$-(\sqrt3+2)$
Work Step by Step
$\frac{1}{\sqrt 3-2}$
$\frac{1}{\sqrt 3-2}*\frac{\sqrt 3+2}{\sqrt 3+2}$
$\frac{\sqrt3+2}{\sqrt {3^2}*\sqrt 3+2*\sqrt 3-2\sqrt 3-4}$
$\frac{\sqrt3+2}{\sqrt {3^2}-4}$
$\frac{\sqrt3+2}{3-4}$
$\frac{\sqrt3+2}{-1}$
$-(\sqrt3+2)$
