Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - Chapter Review - 10-6 Trigonometric Ratios - Page 644: 57

Answer

BC = 6.3, AB=10.2

Work Step by Step

$tan 52 = AC/BC$ $1.28 = 8/BC$ $1.28*BC = 8/BC*BC$ $1.28*BC = 8$ $1.28*BC/1.28 = 8/1.28$ $BC = 6.25$ $AC^2 + BC^2 = AB^2$ $8^2 + 6.3^2 = AB^2$ $64 + 39.69 = AB^2$ $103.69 = AB^2$ $\sqrt {103.69} = \sqrt{AB^2}$ $10.2 = AB$
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