Answer
6.7 = BC, 10 = AC
Work Step by Step
$sin 34 = BC/AB$
$.5592 = BC/12$
$.5592*12 = BC/12*12$
$6.7 = BC$
$12^2=6.7^2+AC^2$
$144 = 44.89 + AC^2$
$99.11 = AC^2$
$\sqrt{99.11} = \sqrt{AC^2}$
$9.95 = AC
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 10 - Radical Expressions and Equations - Chapter Review - 10-6 Trigonometric Ratios - Page 644: 56
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