Answer
$\boxed{3x+1}$,$\boxed{2x-5}$ and $\boxed{x^2}$
Work Step by Step
First of all, you must take $x^2$:
$x^2(6x^2-13x-5)$
Use Middle-term factoring to factor $6x^2-13x-5$
$6x^2 - 15x + 2x - 5$
$3x(2x-5) +1 (2x-5)$
$(3x+1)(2x-5)$
The dimensions are
$\boxed{3x+1}$,$\boxed{2x-5}$ and $\boxed{x^2}$
