Answer
Answer choice $G$: $(3,0)$
Work Step by Step
In order to find out the solution for a system, make sure both equations are in $y=$ format.
$y = x^2 + 2x-15$
$y = 4x - 12$
Solve the quadratic equation with $\frac{-b \pm \sqrt{b^2-4ac}}{2a}$.
$a = 1$
$ b = 2 $
$ c = -15$
$\frac{-2 \pm \sqrt{64}}{2}$.
The solutions are $(3,0)$ and $(-5,0)$.
When you plug these coordinates into the linear equation, $(3,0)$ is the only one that works. Therefore, the answer is $\boxed{G}$.
