Answer
$x=0.1$ or $x=-0.3$
Work Step by Step
$64x^2+12x-1=0$
Use the quadratic formula.
$x=\frac{-(12)+\sqrt (12)^2-4.(64).(-1)}{2.(64)}$
$x=\frac{-12 \pm 20}{128}$
$x=\frac{-12+20}{128}$ or $x=\frac{-12- 20}{128}$
$x=0.1$ or $x=-0.3$
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