Answer
$x=\pm \sqrt 14 -3$
Work Step by Step
$x^2+6x-5=0$
$x^2+6x+9=14$
$(x+3)^2=14$
$x+3=\pm \sqrt 14$
$x=\pm \sqrt 14 -3$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 9 - Quadratic Functions and Equations - Chapter Review - Page 605: 30
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