Answer
There are two solutions for the equation, $\pm 4$
Work Step by Step
$4n^2=64$
$n^2=16$
$n=\pm 4$
There are two solutions for the equation, $\pm 4$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 9 - Quadratic Functions and Equations - Chapter Review - Page 604: 22
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