Answer
See the graph
Work Step by Step
We are given:
$y=-2x^2-3x+10$
Let's list some values:
$x=-2 \rightarrow y=-10$
$x=-1 \rightarrow y=5$
$x=0 \rightarrow y=10$
$x=1 \rightarrow y=5$
$x=2 \rightarrow y=-10$
The x-coordinate of the vertex is given by $x=\frac{-b}{2a}=\frac{-(-3)}{2.(-2)}=-\frac{3}{4}$
Find the y-coordinate of the vertex $y=-2(-\frac{3}{4})^2-3(-\frac{3}{4})+10=\frac{89}{8}$
Hence, the vertex is $(-\frac{3}{4},\frac{89}{8})$.
