Answer
$x=12$
$x={-\dfrac{26}{10}}$
Work Step by Step
$x=\dfrac{-b±{\sqrt {b^{2}-4ac}}}{2a}$ and $5x^{2}-47x-156=0$.Therefore, $a=5$,$b=-47$ and $c=-156$
Substitute the values:
$x=\dfrac{-(-47)±{\sqrt {-47^{2}-4(5)(-156)}}}{2(5)}$
=$\dfrac{47±{\sqrt {2209+3120}}}{10}$
=$\dfrac{47± {\sqrt {5329}}}{10}$
=$\dfrac{47±73}{10}$
Separate the equation into plus and minus equations:
$x=\dfrac{47+73}{10}=12$
$x=\dfrac{47-73}{10}={-\dfrac{26}{10}}$
